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### How does the low specific heat capacity of the material makes it a good thermal conductor?

How does the low **Specific heat capacity** of the material makes it a good thermal conductor?
__Answer:__ specific heat indicates how much energy needed to increase the temp of a material
conductivity indicates how well it transfers energy
these properties are not always related however.....
if you are looking for a thermal conduction you want it to transfer heat energy not absorb it -
low specific heat means it will heat up or cool down with less energy transfered- and it does not hold on to as much thermal energy- this is often useful to conduct heat __Category:__ Physics

### To find the specific heat capacity of water, why is it important to use a copper calorimeter?

I already know that the **Specific heat capacity** of copper is easy to find so it makes it easy to work with, but why would I want to use a material with such a high conductivity to test the **Specific heat capacity** of water when the point is to try and insulate the water to be able to properly measure its temperature rise?
This is for my A2 physics coursework, any help would be greatly appreciated.
__Answer:__ I reckon it might be so that the calorimeter and the water will be at the same temperature so that you can apply the formula that uses the **Specific heat capacity** of copper.
Think of it this way: if your calorimeter was made of 1kg of plastic, and the water rise is 50 degrees, then the inside of the container will rise by 50 degrees (representing perhaps 0.25kg of the weight of the container), but the outside of the container will be at around room temperature (i.e. temperature rise = 0), so the heat energy absorbed by the container will no longer simply be Q=m.c.dT, you'll have a certain mass with a certain temperature rise (the part of the container in contact with the water), another mass with a smaller temperature rise (the outside of the container in contact with the air), and countless pieces in between, each at an intermediate temperature and of different mass, so this would be an extremely complicated problem requiring integration to solve accurately (don't know if you've heard of integration yet... it's like an infinite ammount of summations).
Using a copper container means that the whole calorimeter, both inside and out is at more or less the same temperature so that you can use the mass of the calorimeter and the temperature rise of the water in your calculation with good accuracy.
I assume that your calorimeter would be well insulated from the atmosphere by lagging or foam to minimize external heat losses - that's how I did this experiment way back :-).
Hope mine is the best answer... please? __Category:__ Physics

### How to answer this specific heat capacity question?

An electric heater warms a 1kg block of copper with 9000J. The **Specific heat capacity** of copper is 380 J/Kg/K. What is the temperature rise?
Please be clear about the units? If the **Specific heat capacity** is in K do I need to have an answer in K or in ºC? Because Ive also read somewhere that the **Specific heat capacity** of copper is 380 J/Kg/ºC. It seems the two are intercangeable...
Thanks!
__Answer:__ Let us break this down..
q=mcat or
heat = mass * heat capacity * change in temperature
we are trying to solve for change in temperature so let us flip the equation around...
heat / (mass * heat capacity) = change in temp
9000 J / (1kg * 380 J/Kg/K)
Keep all the units matching (kg and kg... j and j.... K and K)
from this we get:
9000 J / 380 JK = change in temp (380 is JK because the mass KG cancels out the KG in the specific heat)
= roughly 23.68 degrees rounded to the hundreths. The J and J cancel So the temperature rose 23.68 K or C. The answer would be the same regardless of whether it is Celcius or Kelvin so you may put whichever you choose!!!
because K = C + 273.13
So when K rises 23 degrees... C rises the exact same amount. __Category:__ Physics

### Constantan- Composition, Properties, Resistivity, Wire and Uses ...

**Specific heat capacity** 0.39 J/(g·K). Thermal Conductivity 19.5 W/(m.K). Elastic Modulus 162 GPa. Elongation at fracture - <45%. Tensile strength – 455 to 860 MPa. Linear Coefficient of thermal Expansion 14.9 × 10-6 K-1 ...

### chem chapter 6 / Flashcards - Create Free Flashcards

What if a question is given in molar heat... -If the **Specific heat capacity** is given in... 15. What is the **Specific heat capacity** for water? ... -The **Specific heat capacity** is 1 cal g-1... 6. What is a calorimeter? ...

### Does the specific heat capacity of water change when measured in a different temperature range?

In an experiment I heated water with 3 initial and final temperatures. By solving the equation Q=mcΔT for c and plugging in the values I got an average **Specific heat capacity** of about 2287J/Kg*K. The actual **Specific heat capacity** of water found in every source is 4190 J/Kg*K. Is the **Specific heat capacity** of water dependent on the range of temperature measured at? If yes, how does the **Specific heat capacity** change?
__Answer:__ Yes, the specific heat capacities of substances comprising molecules like water are not fixed constants and will vary somewhat depending on its temperature. Accordingly, the temperature at which the measurement is made is usually also specified. Examples of two common ways to cite the specific heat of water are as follows:
Water (liquid): cp = 4.1855 J g–1 K–1 (15 °C), and
Water (liquid): CvH = 74.539 J mol–1 K–1 (25 °C) __Category:__ Physics

### How to determine the specific heat capacity of a metal?

A 20.0-g sample of an unknown metal is heated to 96.0°C and is placed in a insulated container containing 126 g of water at a temperature of 20.4°C. After the metal cools, the final temperature of the metal and water is 23.2°C. Calculate the **Specific heat capacity** of the metal, assuming that no heat escapes to the surroundings.
__Answer:__ heat lost by the metal = heat gained by the water
mCdT metal = m C dT water
(20.0 grams)(C)(72.8 drop in temp) = (126 g)(4.184 J/g-C)(2.8 rise in temp)
1456 (C) = 1476 Joules
C of the metal = 1.01 J/g-C __Category:__ Chemistry

### Chemistry Tutorial : Heat Capacity Calculations

**Specific heat capacity** (Cg) of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1oC (or by 1 K). ...

### Calorimetry: Specific Heat Capacity of Copper

**Specific heat capacity** of Copper. Concepts. Calorimeters are designed to be well -insulated, so no heat is gained from or lost to the surroundings. ...

### How do you calculated the specific heat capacity of this metal?

When 27 g of a metal at 84◦C is added to
53 g of water at 30◦C, the temperature of the
water rises to 37.1◦C. What is the specific
heat capacity of the metal? Assume no heat
ws lost to the surroundings.
Answer in units of
Jg /·◦ C
.
__Answer:__ Q=cmΔT
where Q is heat added or removed, c is specific heat, m is mass, and ΔT is the change in temperature (or Tfinal-Tinitial).
Q=54 J
m=27 g
ΔT=7.1˚ C
c=?
Now substitute what you know.
54=c(27)(7.1)
Rearrange with algebra to get c by itself:
54/(27*7.1)=c
c=.28169 J/g•C
Answers:
0.281 J/g•C
281 J/kg•K __Category:__ Chemistry

### What is the specific heat capacity of the mineral?

A geologist is trying to identify an unknown mineral by measuring its **Specific heat capacity**. A 307g sample of the mineral was heated to 98.7C and placed into a calorimeter containing 72.4 g of water at 23.6C. The heat capacity of the calorimeter was 15.7 J/K. The final temperature in the calorimeter was 32.4C. What is the **Specific heat capacity** of the mineral?
Thanks for the help!
__Answer:__ MCT = MCT
Heat loss = heat gained
307 * C * (98.7-32.4) = 72.4* 4.2* (32.4-23.6) [ Assuming no heat loss to the container or environment]
C= 2675.904 / 307 * (98.7-32.4)
= 2675.904 / 20354.1
= 0.13 j/g degree C __Category:__ Chemistry

### Specific Heat and Heat Capacity

Thus, the specific heat of a gallon of milk is equal to the specific heat of a quart of milk. A related quantity is called the heat capacity (C). of an ...

### What is the specific heat capacity for tin and zinc?

What is the **Specific heat capacity** for tin and zinc, in the form of Joules per kilograms degrees Celsius?
For example, to my knowledge Aluminums **Specific heat capacity** is 9.1 x 10 to the power of 2 J/Kg degrees Celsius.
__Answer:__ http://www.engineeringtoolbox.com/specific-heat-metals-d_152.html
tin: 0.21 kJ/kg-C
aka
2.1 X 10^2 J/kg-C
zinc: 0.39 kJ/kg-C
aka
3.9 X 10^2 J/kg-C __Category:__ Chemistry

### Specific Heat Capacity

The **Specific heat capacity** of a solid or liquid is defined as the heat required to raise unit mass of substance by one degree of temperature. ...

### How is specific heat capacity important to society?

In what ways does **Specific heat capacity** and an understanding of this contribute to society? As in, what do we use or utilize that incorporates a knowledge of this/how does it make things easier...everyday thing, in industry, just everything that makes it important...
Also, how and why do solutes affect the **Specific heat capacity** and/or boiling point of a substance or solution? And how could this be utilized in society?
__Answer:__ The Specific Heat is the amount of heat required to change a unit mass of a substance by one degree in temperature. To see how this is a factor in materials selection for common items browse this interesting site, it also expands the understanding of just what the function is.
http://heatmozac.blogspot.com/2008/09/42-specific-heat-capacity-applications.html
hth __Category:__ Engineering

### Specific Heat

Specific Heat. The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius. The relationship between heat ...

### Difference Between Heat Capacity and Specific Heat | Difference ...

Heat Capacity vs Specific Heat When a substance is heated its temperature rises, and when it is cooled its temperature decreases. The difference in.

### Specific Heat capacity and Molar specific Heat capacity | Ask Physics

Chaitanya asked: how to calculate molar the heat capacity of a gas given cp and cv of the gas? Answer: **Specific heat capacity** of a substance.

### What is the specific heat capacity of the human body?

I know that the **Specific heat capacity** of water is 4186J/kgK and Im interested if the **Specific heat capacity** of the human body is smaller or bigger of that. The body should be thermal insulator and should therefore have a bigger **Specific heat capacity**.
__Answer:__ The average **Specific heat capacity** of a human body is approximately 3500 J/kgK __Category:__ Physics

### Specific Heat Capacity | Mini Physics - Free Physics Notes And More!

**Specific heat capacity**, c, of a body is defined as the amount of heat (Q) required to raise the temperature (θ) of a unit mass of it by one degree, without going through a change in state. - The greater the mass, ...

### Thermal physics; specific heat capacity | bnewsnow

Thermal physics; **Specific heat capacity**. Despite the fact that cypher temperatures on field make been multiplicative from gathering to year, globally averaged aboveground temperatures from 2000 to 2010 acquire shown only ...

### Specific Heat Capacity - DiracDelta Science & Engineering Encyclopedia

**Specific heat capacity** - Science and Engineering Encyclopedia.

### Thermal Physics Specific Heat Capacity | Newz of Today

Thermal Physics **Specific heat capacity**. The approach of the problem, all variables and seen/known data. In an experiment to measure the temperature of the flame of a Bunsen burner, a piece of copper of 0.12 kg mass is ...

### Specific Heat Capacity - Engineering ToolBox

The Specific Heat is the amount of heat required to change a unit mass of a substance by one degree in temperature.

### What is the specific heat capacity for water saturated iron filings?

The **Specific heat capacity** of iron is generally cited at 0.107 cal/gm/deg C, but what about saturated iron filings? The disticntion may be important for the following problem:
If I send a 95 liter slug of 47 degree C water through 2 meters of saturated iron filings (say 1 meter deep by 3 meters wide) at a temperature of 12.5 degrees C, will the heat pulse due to conduction get there before the convective heat pulse?
Thanks
__Answer:__ You need a packing fraction for any serious attempt to solve the first question. For the 2nd question, the heat pulse due to convection will pass through before any conductive heat pulse unless you have solid iron through which the water cannot pass. __Category:__ Engineering

### What is the specific heat capacity of the following problem?

A 10.0g piece of metal at 100 degrees Celsius is transferred to a calorimeter containing 50.0mL of water initially at 23.0 degrees Celsius. Calculate the **Specific heat capacity** of the metal if the heat Capacity of the calorimeter Ccal is 25.0J/K. The final temperature is 25.6 degrees Celsius.
__Answer:__ the metal cooled from 100C down to 25.6C
while the water & the calorimeter warmed from 23 C up to 25.6C
heat lost by the metal = heat gained by water & by the calorimeter
- m C dT metal = m C dT water & C dT calorimeter
- [10(C)(25.6C -100)] = (50g)(4.184J/g-C)(25.6 - 23) & 25.0J/K(25.6 - 23C)
744(C) = 543.92 & 65
744 (C) = 608.92
C = 0.818 J/g-C
__Category:__ Chemistry

### What is the specific heat capacity of the alloy?

A 10.25 grams sample of metal alloy is heated to 99.10 C and then is dropped into 20.0 g of water in a calorimeter at 18.53 C. If the water temperature increases to 22.03 C, what is the **Specific heat capacity** of the alloy? The **Specific heat capacity** for water is 4.184 J/ gC.
__Answer:__ -q(alloy)=q(water)
-(10.25)(c alloy)(22.03 - 99.10) = (20)(4.184)(22.03-18.53)
c alloy = (20)(4.184)(22.03-18.53) / -(10.25)(22.03 - 99.10)
c alloy = 0.371 J/g C __Category:__ Chemistry

### What is the specific heat capacity of this metal?

How would you set this formula up?
I know it would be -mcΔT = mcΔT
A piece of metal with a mass of 15.0 is heated to 97°C. The metal is placed in 80g of water at 22°C. The temperature of the water rises to 50.5°C. What is the **Specific heat capacity** of the metal?
__Answer:__ Essentially, the the heat energy gained by the water= the heat energy lost by the metal
Heat energy gained by the water, Q= mcΔT where m is the mass of the water, c is the **Specific heat capacity** of water and ΔT is the change in temperature of the water.
Q= 15.0 x 4.186 x (50.5-22)
= 1789.515 J
Heat energy gained by the piece of metal, Q= mcΔT where m is the mass of the metal, c is the **Specific heat capacity** of the metal and ΔT is the change in temperature of the metal which is 28.5°C
Rearranging the formula, we get c= Q/mΔT
= 1789.515/(80)(28.5)
= 0.784875J/kg/°C(answer)
I hope this helps! __Category:__ Chemistry

### What is the specific heat capacity of the metal?

A 10.0 g piece of metal at 100 °C is transferred to a calorimeter containing 50.0 mL of water initially at is 25.0 °C. Calculate the **Specific heat capacity** of the metal if the heat the heat capacity of the calorimeter Ccal is 25.0 J/°K. The final temperature, Tfinal is 25.6 °C.
__Answer:__ The heat lost by the metal = the heat absorbed by the water + calorimeter.
Heat absorbed by water = mass H2O x sp.ht. H2O x delta T =
(50.0 g)(4.184 J/g K)(25.6 - 25.0) = 126 J
Heat absorbed by calorimeter = Cp x delta T = (25.0 J/K)(25.6 - 25.0) = 15 J
Total heat absorbed by water + calorimeter = 126 + 15 = 141 J = heat lost by metal
Heat lost by metal = mass metal x sp.ht. metal x delta T =
(10.0 g)(sp. ht. metal)(100 - 25.6) = 744 x sp.ht. metal
141 = 744 x sp.ht. metal
141 / 744 = sp.ht. metal = 0.190 J/g K
I have assumed that the density of water = 1.00 g/mL (so that 50 mL = 50 g). Also, delta T in Celsius is the same as delta T in Kelvins.
__Category:__ Chemistry

### How does specific heat capacity affect climate in different regions?

How does **Specific heat capacity** affect climate in different regions? caqn some body plz help, i have to write a paragraph 4 this answer!!! plz plz thanx ... Specific Heat The specific heat is the amount of heat per unit mass ...

### What is the specific heat capacity of the specimen?

A precious-stone dealer wishes to find the **Specific heat capacity** of a 0.040-kg gemstone. The specimen is heated to 95.0°C and then placed in a 0.13-kg copper vessel that contains 0.072 kg of water at equilibrium at 25.0°C. The loss of heat to the external environment is negligible. When equilibrium is established, the temperature is 31.0°C.
__Answer:__ Heat lost from the water and copper equals heat gained by gem.
specific heat of water is 4.186 kJ/kgC
specific heat of copper is 386 J/kgC
4.186 kJ/kgC x 0.072 kg x (31–25) + 0.386 J/kgC x 0.13 kg x (31–25) = SH x 0.04 kg x (95–31)
1.808 + 0.301 = SH x 2.56
SH = 0.824 kJ/kgC or 824 J/kgC
edit, corrected arith
. __Category:__ Engineering

### Heat capacity - Wikipedia, the free encyclopedia

... density and its **Specific heat capacity** on a per-mass basis. ...